Optimal. Leaf size=477 \[ \frac{\sqrt [4]{a+b} \cos ^2(c+d x) \left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right ) \sqrt{\frac{(a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a}{\left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a+b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac{1}{2} \left (1-\frac{\sqrt{a}}{\sqrt{a+b}}\right )\right )}{2 a^{3/4} d \sqrt{a+b \sin ^4(c+d x)}}-\frac{\sqrt [4]{a+b} \cos ^2(c+d x) \left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right ) \sqrt{\frac{(a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a}{\left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a+b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac{1}{2} \left (1-\frac{\sqrt{a}}{\sqrt{a+b}}\right )\right )}{a^{3/4} d \sqrt{a+b \sin ^4(c+d x)}}+\frac{\sqrt{a+b} \sin (c+d x) \cos (c+d x) \left ((a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a\right )}{a d \sqrt{a+b \sin ^4(c+d x)} \left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right )}-\frac{\cos ^2(c+d x) \cot (c+d x) \left ((a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a\right )}{a d \sqrt{a+b \sin ^4(c+d x)}} \]
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Rubi [A] time = 0.365576, antiderivative size = 477, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.24, Rules used = {3232, 1123, 12, 1139, 1103, 1195} \[ \frac{\sqrt [4]{a+b} \cos ^2(c+d x) \left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right ) \sqrt{\frac{(a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a}{\left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a+b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac{1}{2} \left (1-\frac{\sqrt{a}}{\sqrt{a+b}}\right )\right )}{2 a^{3/4} d \sqrt{a+b \sin ^4(c+d x)}}-\frac{\sqrt [4]{a+b} \cos ^2(c+d x) \left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right ) \sqrt{\frac{(a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a}{\left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a+b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac{1}{2} \left (1-\frac{\sqrt{a}}{\sqrt{a+b}}\right )\right )}{a^{3/4} d \sqrt{a+b \sin ^4(c+d x)}}+\frac{\sqrt{a+b} \sin (c+d x) \cos (c+d x) \left ((a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a\right )}{a d \sqrt{a+b \sin ^4(c+d x)} \left (\sqrt{a+b} \tan ^2(c+d x)+\sqrt{a}\right )}-\frac{\cos ^2(c+d x) \cot (c+d x) \left ((a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a\right )}{a d \sqrt{a+b \sin ^4(c+d x)}} \]
Antiderivative was successfully verified.
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Rule 3232
Rule 1123
Rule 12
Rule 1139
Rule 1103
Rule 1195
Rubi steps
\begin{align*} \int \frac{\cot ^2(c+d x)}{\sqrt{a+b \sin ^4(c+d x)}} \, dx &=\frac{\left (\cos ^2(c+d x) \sqrt{a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{x^2 \sqrt{a+2 a x^2+(a+b) x^4}} \, dx,x,\tan (c+d x)\right )}{d \sqrt{a+b \sin ^4(c+d x)}}\\ &=-\frac{\cos ^2(c+d x) \cot (c+d x) \left (a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)\right )}{a d \sqrt{a+b \sin ^4(c+d x)}}+\frac{\left (\cos ^2(c+d x) \sqrt{a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)}\right ) \operatorname{Subst}\left (\int \frac{(a+b) x^2}{\sqrt{a+2 a x^2+(a+b) x^4}} \, dx,x,\tan (c+d x)\right )}{a d \sqrt{a+b \sin ^4(c+d x)}}\\ &=-\frac{\cos ^2(c+d x) \cot (c+d x) \left (a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)\right )}{a d \sqrt{a+b \sin ^4(c+d x)}}+\frac{\left ((a+b) \cos ^2(c+d x) \sqrt{a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{a+2 a x^2+(a+b) x^4}} \, dx,x,\tan (c+d x)\right )}{a d \sqrt{a+b \sin ^4(c+d x)}}\\ &=-\frac{\cos ^2(c+d x) \cot (c+d x) \left (a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)\right )}{a d \sqrt{a+b \sin ^4(c+d x)}}+\frac{\left (\sqrt{a+b} \cos ^2(c+d x) \sqrt{a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+2 a x^2+(a+b) x^4}} \, dx,x,\tan (c+d x)\right )}{\sqrt{a} d \sqrt{a+b \sin ^4(c+d x)}}-\frac{\left (\sqrt{a+b} \cos ^2(c+d x) \sqrt{a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{a+b} x^2}{\sqrt{a}}}{\sqrt{a+2 a x^2+(a+b) x^4}} \, dx,x,\tan (c+d x)\right )}{\sqrt{a} d \sqrt{a+b \sin ^4(c+d x)}}\\ &=-\frac{\cos ^2(c+d x) \cot (c+d x) \left (a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)\right )}{a d \sqrt{a+b \sin ^4(c+d x)}}+\frac{\sqrt{a+b} \cos (c+d x) \sin (c+d x) \left (a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)\right )}{a d \sqrt{a+b \sin ^4(c+d x)} \left (\sqrt{a}+\sqrt{a+b} \tan ^2(c+d x)\right )}-\frac{\sqrt [4]{a+b} \cos ^2(c+d x) E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a+b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac{1}{2} \left (1-\frac{\sqrt{a}}{\sqrt{a+b}}\right )\right ) \left (\sqrt{a}+\sqrt{a+b} \tan ^2(c+d x)\right ) \sqrt{\frac{a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)}{\left (\sqrt{a}+\sqrt{a+b} \tan ^2(c+d x)\right )^2}}}{a^{3/4} d \sqrt{a+b \sin ^4(c+d x)}}+\frac{\sqrt [4]{a+b} \cos ^2(c+d x) F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{a+b} \tan (c+d x)}{\sqrt [4]{a}}\right )|\frac{1}{2} \left (1-\frac{\sqrt{a}}{\sqrt{a+b}}\right )\right ) \left (\sqrt{a}+\sqrt{a+b} \tan ^2(c+d x)\right ) \sqrt{\frac{a+2 a \tan ^2(c+d x)+(a+b) \tan ^4(c+d x)}{\left (\sqrt{a}+\sqrt{a+b} \tan ^2(c+d x)\right )^2}}}{2 a^{3/4} d \sqrt{a+b \sin ^4(c+d x)}}\\ \end{align*}
Mathematica [C] time = 11.231, size = 378, normalized size = 0.79 \[ -\frac{\cot (c+d x) \sqrt{8 a-4 b \cos (2 (c+d x))+b \cos (4 (c+d x))+3 b}}{2 \sqrt{2} a d}-\frac{\cos ^4(c+d x) \left (\frac{\left (\sqrt{a} \sqrt{b}+i a\right ) \sec ^2(c+d x) \sqrt{1+\left (1-\frac{i \sqrt{b}}{\sqrt{a}}\right ) \tan ^2(c+d x)} \sqrt{1+\left (1+\frac{i \sqrt{b}}{\sqrt{a}}\right ) \tan ^2(c+d x)} \left (E\left (i \sinh ^{-1}\left (\sqrt{1-\frac{i \sqrt{b}}{\sqrt{a}}} \tan (c+d x)\right )|\frac{\sqrt{a}+i \sqrt{b}}{\sqrt{a}-i \sqrt{b}}\right )-F\left (i \sinh ^{-1}\left (\sqrt{1-\frac{i \sqrt{b}}{\sqrt{a}}} \tan (c+d x)\right )|\frac{\sqrt{a}+i \sqrt{b}}{\sqrt{a}-i \sqrt{b}}\right )\right )}{\sqrt{1-\frac{i \sqrt{b}}{\sqrt{a}}}}+a \tan (c+d x) \sec ^4(c+d x)+b \tan ^5(c+d x)\right )}{a d \sqrt{\cos ^4(c+d x) \left ((a+b) \tan ^4(c+d x)+2 a \tan ^2(c+d x)+a\right )}} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.71, size = 0, normalized size = 0. \begin{align*} \int{ \left ( \cot \left ( dx+c \right ) \right ) ^{2}{\frac{1}{\sqrt{a+b \left ( \sin \left ( dx+c \right ) \right ) ^{4}}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cot \left (d x + c\right )^{2}}{\sqrt{b \sin \left (d x + c\right )^{4} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\cot \left (d x + c\right )^{2}}{\sqrt{b \cos \left (d x + c\right )^{4} - 2 \, b \cos \left (d x + c\right )^{2} + a + b}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cot ^{2}{\left (c + d x \right )}}{\sqrt{a + b \sin ^{4}{\left (c + d x \right )}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cot \left (d x + c\right )^{2}}{\sqrt{b \sin \left (d x + c\right )^{4} + a}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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